Source code for pyro.distributions.transforms.cholesky
import math
import torch
from torch.distributions import constraints
from torch.distributions.transforms import Transform
from pyro.distributions.constraints import corr_cholesky_constraint
def _vector_to_l_cholesky(z):
D = (1.0 + math.sqrt(1.0 + 8.0 * z.shape[-1])) / 2.0
if D % 1 != 0:
raise ValueError("Correlation matrix transformation requires d choose 2 inputs")
D = int(D)
x = torch.zeros(z.shape[:-1] + (D, D), dtype=z.dtype, device=z.device)
x[..., 0, 0] = 1
x[..., 1:, 0] = z[..., :(D - 1)]
i = D - 1
last_squared_x = torch.zeros(z.shape[:-1] + (D,), dtype=z.dtype, device=z.device)
for j in range(1, D):
distance_to_copy = D - 1 - j
last_squared_x = last_squared_x[..., 1:] + x[..., j:, (j - 1)].clone()**2
x[..., j, j] = (1 - last_squared_x[..., 0]).sqrt()
x[..., (j + 1):, j] = z[..., i:(i + distance_to_copy)] * (1 - last_squared_x[..., 1:]).sqrt()
i += distance_to_copy
return x
[docs]class CorrLCholeskyTransform(Transform):
"""
Transforms a vector into the cholesky factor of a correlation matrix.
The input should have shape `[batch_shape] + [d * (d-1)/2]`. The output will have
shape `[batch_shape] + [d, d]`.
Reference:
[1] `Cholesky Factors of Correlation Matrices`, Stan Reference Manual v2.18, Section 10.12
"""
domain = constraints.real
codomain = corr_cholesky_constraint
bijective = True
sign = +1
event_dim = 1
def __eq__(self, other):
return isinstance(other, CorrLCholeskyTransform)
def _call(self, x):
z = x.tanh()
return _vector_to_l_cholesky(z)
def _inverse(self, y):
if (y.shape[-2] != y.shape[-1]):
raise ValueError("A matrix that isn't square can't be a Cholesky factor of a correlation matrix")
D = y.shape[-1]
z_tri = torch.zeros(y.shape[:-2] + (D - 2, D - 2), dtype=y.dtype, device=y.device)
z_stack = [
y[..., 1:, 0]
]
for i in range(2, D):
z_tri[..., i - 2, 0:(i - 1)] = y[..., i, 1:i] / (1 - y[..., i, 0:(i - 1)].pow(2).cumsum(-1)).sqrt()
for j in range(D - 2):
z_stack.append(z_tri[..., j:, j])
z = torch.cat(z_stack, -1)
return torch.log1p((2 * z) / (1 - z)) / 2
[docs] def log_abs_det_jacobian(self, x, y):
# Note dependence on pytorch 1.0.1 for batched tril
tanpart = x.cosh().log().sum(-1).mul(-2)
matpart = (1 - y.pow(2).cumsum(-1).tril(diagonal=-2)).log().div(2).sum(-1).sum(-1)
return tanpart + matpart